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Physical electronics devices and ics miscellaneous

Physical Electronics Devices and ICs

  1. Find I1 and I2 in diagram shown below in terms of VS assume VT = 0.7 volt for all diode—


    1. I1 =
      5 – Vx
      if 0 < VS < 0.7 V and I1 = I2 = 1.8 mA if VS > .7 V
      2K
    2. I2 = I1 =
      5 – Vx
      if VS > .7 V I2 = 1.8 mA if 0 < VS < 0.7 V
      2K
    3. I2 = 1.8 mA if VS > 0.7 V I1 =
      5 – Vx
      if VS > 0.7 V
      2K
    4. None of the above
Correct Option: A

From figure we see that here everything depends upon voltage. Vx

I1 =
5 – Vx
2K

if 0 < VS < .7 V
Also Vx = VS + .7 V

If VS > 0.7 V then
The diode D1 will be in reverse biased and
I1 = I2 =
5 – 1.4
= 1.8 mA
2K

Where, 1.4 V is the voltage drop across diode D2 and D3



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