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Find I1 and I2 in diagram shown below in terms of VS assume VT = 0.7 volt for all diode—
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I1 = 5 – Vx if 0 < VS < 0.7 V and I1 = I2 = 1.8 mA if VS > .7 V 2K -
I2 = I1 = 5 – Vx if VS > .7 V I2 = 1.8 mA if 0 < VS < 0.7 V 2K -
I2 = 1.8 mA if VS > 0.7 V I1 = 5 – Vx if VS > 0.7 V 2K - None of the above
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Correct Option: A
From figure we see that here everything depends upon voltage. Vx
I1 = | 2K |
if 0 < VS < .7 V
Also Vx = VS + .7 V

If VS > 0.7 V then
The diode D1 will be in reverse biased and
I1 = I2 = | = 1.8 mA | 2K |
Where, 1.4 V is the voltage drop across diode D2 and D3