In figure both transistors are identical and have a high

In figure both transistors are identical and have a high value of beta. Take the do base emitter voltage drop as 0.7 volt and kT/q = 25 mV. The small signal low frequency voltage gain (V₀ / V_i) is equal to—

Given R_C = 1.2 kΩ, R_E = 1 kΩ from the given

The gain A_V =		V₀	= -	R_C	(by using direct formula)
		V_i		β

or A_V =	1.2 kΩ	= – 1.2
	1 kΩ

Note: Usually A_V =	–h_fe · R_C
	(1 + h_fe) R_E + h_ie

assuming very high gain factor i.e. h_fe >> 1 and h_ie is very small as compare to R_E.

A_V ≈ -	R_C
	R_E

Hence alternative (D) is the correct answer.