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What is the output of this program?
#include <iostream>
#include <deque>
using namespace std;
int main ()
{
deque<int> DequeData (6);
deque<int>::reverse_iterator RevIter = DequeData.rbegin();
int k = 0;
for (RevIter = DequeData.rbegin(); RevIter != DequeData.rend(); ++RevIter)
*RevIter = ++k;
for (deque<int> :: iterator iter = DequeData.begin();
iter != DequeData.end(); ++iter)
cout << ' ' << *iter;
return 0;
}
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- 6 5
- 6 5 4
- 6 5 4 3
- 6 5 4 3 2
- 6 5 4 3 2 1
Correct Option: E
In this program, We used the operation of rbegin and rend on dequeue and produced the result.