-
What will be the output of the following C code?
#include <stdio.h>
int main()
{
int num[4][5];
f(num);
}
void f(int (*num)[4])
{
int n1 = 15, n2 = 13, n;
num[0] = &n1;
num[1] = &n2;
for (n = 0; n < 2; n++)
printf("%d\n", *num[n]);
}
-
- Compilation Error
- Garbage value
- Undefined behaviour
- Compilation Error
- segmentation fault/code crash
Correct Option: D
Compilation Error
main.c: In function ‘main’:
main.c:5:9: warning: implicit declaration of function ‘f’ [-Wimplicit-function-declaration]
f(num);
^
main.c: At top level:
main.c:7:10: warning: conflicting types for ‘f’
void f(int (*num)[4])
^
main.c:5:9: note: previous implicit declaration of ‘f’ was here
f(num);
^
main.c: In function ‘f’:
main.c:10:16: error: assignment to expression with array type
num[0] = &n1;
^
main.c:11:16: error: assignment to expression with array type
num[1] = &n2;
