What is the output of this C code?#include <stdio.h>int

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What is the output of this C code?

#include <stdio.h>
int main()
{
    char *p[1] = {"Interview Mania"};
    printf("%s", (p)[0]);
    return 0;
}

1. Compile time error
2. Undefined behavior
3. Interview Mania
4. None of the mentioned

Correct Option: C

The output will be “Interview Mania”. Here is why:

{"Interview Mania"} denotes an array of strings and char *p [1] is declaring an array to hold 1 character pointer. The assignment operator will make the first character pointer point to "Interview Mania".