Two similar springs P and Q have spring constants KP and

Two similar springs P and Q have spring constants K_P and K_Q, such that K_P > K_Q. They are stretched, first by the same amount (case a,) then by the same force (case b). The work done by the springs W_P and W_Q are related as, in case (a) and case (b), respectively

1. W_P = W_Q ; W_P = W_Q
2. W_P > W_Q ; W_Q > W_P
3. W_P < W_Q ; W_Q < W_P
4. W_P = W_Q ; W_P > W_Q

As we know work done in stretching spring w =	1	Kx²
	2

where k = spring constant x = extension
Case (a) If extension (x) is same,

W =	1	Kx²
	2

So,W_P > W_Q(K_P > K_Q)

Case (b) If spring force (F) is same W =	F²
	2K

So,W_Q > W_P