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When a long spring is stretched by 2 cm, its potential energy is U. If the spring is stretched by 10 cm, the potential energy stored in it will be
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- 25 U
- U/5
- 5 U
- 10 U
Correct Option: A
| If k be the spring constant, then U = | × k × (2)2 = 2 k | |
| 2 |
| Ufinal = | × k × (10)2 = 50 k | |
| 2 |
| ⇒ | = | = | ||||
| Ufinal | 50k | 25 |
⇒ Ufinal = 25 U
