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A rubber ball is dropped from a height of 5m on a plane, where the acceleration due to gravity is not shown. On bouncing it rises to 1.8 m. The ball loses its velocity on bouncing by a factor of
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16 25 -
2 5 -
3 5 -
9 25
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Correct Option: B
According to principle of conservation of energy
Loss in potential energy = Gain in kinetic energy
| ⇒ mgh = | mv2 ⇒ v = √2gh | |
| 2 |
If h1 and h2 are initial and final heights, then
v1 = √2gh1 , v2 = √2gh2
Loss in velocity , ∆v = v1 - v2 = √2gh1 - √2gh2
∴ Fractional loss in velocity


| = 1 - √0.36 = 1 - 0.6 = 0.4 = | ||
| 5 |