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If the momentum of a body is increased by 50%, then the percentage increase in its kinetic energy is
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- 50%
- 100%
- 125%
- 200%
Correct Option: C
Initial momentum (p1) = p; Final momentum (p2) = 1.5 p and initial kinetic energy (K1) = K.
Kinetic energy (K) = | ∝ p2 | |
2m |
or, | = | ![]() | ![]() | 2 | = | ![]() | ![]() | 2 | = | ||||
K2 | p2 | 1.5 p | 2.25 |
or, K2 = 2.25 K.
Therefore, increase in kinetic energy is 2.25 K – K = 1.25 K or 125%.