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Two spheres A and B of masses m1 and m2 respectively collide. A is at rest initially and
to the original direction. The mass A moves after collision in the direction.B is moving with velocity v along x-axis. After collision B has a velocity v in a direction perpendicular 2
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- Same as that of B
- Opposite to that of B
- θ = tan–1 (1/2) to the x-axis
- θ = tan–1 (–1/2) to the x-axis
Correct Option: C
u = 0
conservation of linear momentum along x-direction
m2v = m1vx ⇒ | = vx | |
m1 |
along y-direction
m2 × | = m1vy ⇒ vy = | ||
2 | 2m1 |
Note : Let A moves in the direction, which makes an angle θ with initial direction i.e.
tan θ = | = | ||||
2m1 | |||||
vx | |||||
2m1 |
tan θ = | ||
2 |
θ = tan-1 | ![]() | ![]() | to the x-axis. | |
2 |