Home » Mechanics » Work, Energy and Power » Question
  1. Two spheres A and B of masses m1 and m2  respectively collide. A is at rest initially and
    B is moving with velocity v along x-axis. After collision B has a velocity
    v
    in a direction perpendicular
    2
    to the original direction. The mass A moves after collision in the direction.
    1. Same as that of B
    2. Opposite to that of B ​
    3. θ = tan–1 (1/2) to the x-axis
    4. θ = tan–1 (–1/2) to the x-axis
Correct Option: C


u = 0 ​
conservation of linear momentum along x-direction

m2v = m1vx
m2v
= vx
m1

along y-direction
m2 ×
v
= m1vy ⇒ vy =
m2v
22m1

Note : Let A moves in the direction, which makes an angle θ with initial direction i.e.
tan θ =
vy
=
m1v
2m1
vx
m2v
2m1

tan θ =
1
2

θ = tan-1
1
to the x-axis.
2



Your comments will be displayed only after manual approval.