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A body of mass m moving with velocity 3 km/h collides with a body of mass 2 m at rest. Now the coalesced mass starts to move with a velocity
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- 1 km/h
- 2 km/h
- 3 km/h
- 4 km/h
Correct Option: A
Applying law of conservation of momentum,
m1u1 + m2u2 = (m1 + m2)v
or, m1u1 = (m1 + m2)v (∵ u2 = 0)
| ⇒ m | = 3m(v) | |
| 3600 |
| ⇒ v = | m/s = 1 km / hr | |
| 3600 |
