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A body of mass 5 kg explodes at rest into three fragments with masses in the ratio 1 : 1 : 3. The fragments with equal masses fly in mutually perpendicular directions with speeds of 21 m/s. The velocity of heaviest fragment in m/s will be
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- 7 √2
- 5 √2
- 3 √2
- √2
Correct Option: A
Masses of the pieces are 1, 1, 3 kg. Hence
(1 × 2 l)2 + (1 × 2 l)2 = (3 × V)2
That is ,V = 7 √2 m / s
