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The height at which the weight of a body becomes 1/16th, its weight on the surface of earth (radius R), is :
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- 5R
- 15R
- 3R
- 4R
Correct Option: C
Let at h height, the weight of a body becomes | th of its weight on the surface. | |
16 |
Wh = 16 Ws....(i)
⇒16 Ws = Ws....(ii)
g' = | ||
(Re + h)2 |
Similarly , g = | ||
Re2 |
= | ⇒ g' = g | ![]() | 1 + | ![]() | -2 | |||||
g | (Re + h)2 | R |
⇒ Wh = 16 Ws
g' = | ||
16 |
g' = 16g | ![]() | 1 + | ![]() | 2 | |
R |
= | ![]() | 1 + | ![]() | -2 | ⇒ 4 = 1 + | |||||
16 | R | R |
h = 3R