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Imagine a new planet having the same density as that of earth but it is 3 times bigger than the earth in size. If the acceleration due to gravity on the surface of earth is g and that on the surface of the new planet is g’, then
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- g’ = (g / 9)
- g’ = 27g
- g’= 9g
- g’= 3g
Correct Option: D
We know that
| g = | = | G |  | πR3 |  | ρ | = | πGRρ | ||||
| 3 | ||||||||||||
| R2 | R2 | 3 | ||||||||||
| = | = | = 3 | ||||
| g | R | R |
∴ g' = 3g
