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The escape velocity of a body on the surface of the earth is 11.2 km/s. If the earth’s mass increases to twice its present value and the radius of the earth becomes half, the escape velocity would become
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- 44.8 km/s
- 22.4 km/s
- 11.2 km/s (remains unchanged)
- 5.6 km/s
Correct Option: B
Escape velcocity 
| Given Me' = 2 Me and Re' = | ||
| 2 |
= √4 = 2
ve' = 2 ve = × 11.2 = 22.4 km/s
