Home » Mechanics » Gravitation » Question
  1. If the gravitational force between two objects were proportional to 1/R (and not as 1/R2) where R is separation between them, then a particle in circular orbit under such a force would have its orbital speed v proportional to
    1. ​ 1/R2
    2. R0
    3. R1
    4. 1 / R
Correct Option: B

F =
k
=
Mv2
RR

Hence , v ∝ R0



Your comments will be displayed only after manual approval.