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The compressibility of water is 4 × 10–5 per unit atmospheric pressure. The decrease in volume of 100 cm3 of water under a pressure of 100 atmosphere will be
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- 0.4 cm3
- 4 × 10–5 cm3
- 0.025 cm3
- 0.004 cm3
Correct Option: A
K = | = | |||
B | P |
Here, P = 100 atm,
K = 4 × 10–5 and V = 100 cm3.
Hence, ∆V = 0.4 cm3