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The cylindrical tube of a spray pump has radius, R, one end of which has n fine holes, each of radius r. If the speed of the liquid in the tube is V, the speed of the ejection of the liquid through the holes is :
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VR2 nr2 -
VR2 n3 r2 -
V2R nr -
VR2 n2 r2
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Correct Option: A
Inflow rate of volume of the liquid = Outflow rate of volume of the liquid
πR2V = nπr2(v) ⇒ V = | = | |||
nπr2 | nr2 |