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An electron is moving round the nucleus of a hydrogen atom in a circular orbit of radius r. The Coulomb force F→ between the two is
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K e2 r→ r3 -
K e2 r̂ r2 -
-K e2 r̂ r3 -
-K e2 r→ r3 where K = 1 4πε0
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Correct Option: D
Charges (–e) on electron and (e) on proton exert a force of attraction given by
Force = (K) | r̂ = | ṙ | ![]() | ∵ r̂ = | ![]() | |||
r2 | r3 | | r | |
Note : Magnitude of Coulomb force is given by
F = | . | |||
4πε0 | r2 |
but in vector form F→ = | . | r→ | ||
4πε0 | r2 |