The mean free path of electrons in a metal is 4 × 10–8

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The mean free path of electrons in a metal is 4 × 10^–8 m. The electric field which can give on an average 2 eV energy to an electron in the metal will be in units of V/m

1. 5 × 10^–11
2. 8 × 10^–11
3. 5 × 10⁷
4. 8 × 10⁷

Correct Option: C

E =	V	=	2
	d		4 × 10^–8

= 0.5 × 10⁸ = 5 × 10⁷ Vm^–1