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Three point charges +q, –q and +q are placed at points (x = 0, y = a, z = 0), (x = 0, y = 0, z = 0) and (x = a, y = 0, z = 0) respectively. The magnitude and direction of the electric dipole moment vector of this charge assembly are
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- √2qa along the line joini points (x = 0, y = 0, z = 0) and (x = a, y = a, z = 0)
- qa along the line joining points (x = 0, y = 0, z = 0) and (x = a, y = a, z = 0)
- √2qa along +ve x direction
- √2qa along +ve y direction
Correct Option: A
Three point charges +q, –2q and +q are placed at points B (x = 0, y = a, z = 0), O (x = 0, y = 0, z = 0) and A(x = a, y = 0, z = 0) The system consists of two dipole moment vectors due to (+q and –q) and again due to (+q and –q) charges having equal magnitudes qa units – one along OA→ and other along OB→ . Hence, net dipole moment,
pnet = √(qa)² + (qa)² = √2 qa along OP→ at an angle 45° with positive X-axis.