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A charge Q is enclosed by a Gaussian spherical surface of radius R. If the radius is doubled, then the outward electric flux will
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- increase four times
- be reduced to half
- remain the same
- be doubled
Correct Option: C
By Gauss’s theorem,
| φ = | ||
| ε0 |
Thus, the net flux depends only on the charge enclosed by the surface. Hence, there will be no effect on the net flux if the radius of the surface is doubled.
