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A hollow cylinder has a charge q coulomb within it. If φ is the electric flux in units of voltmeter associated with the curved surface B, the flux linked with the plane surface A in units of voltmeter will be
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q 2ε0 -
φ 3
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q - φ ε0 -
1 q - φ 2 ε0
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Correct Option: D
Since φtotal = φA + φB + φC = | ||
ε0 |
where q is the total charge.
As shown in the figure, flux associated with the curved surface B is φ = φB
Let us assume flux linked with the plane surfaces A and C be
φA = φC = φ'
Therefore, | = 2φ' + φB = 2φ' + φ | |
ε0 |
⇒ φ' = | ![]() | - φ | ![]() | ||
2 | ε0 |