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In the Young’s double-slit experiment, the intensity of light at a point on the screen where the path difference is λ is K, (λ being the wave length of light used). The intensity at a point where the path difference is λ /4, will be:
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- K
- K/4
- K/2
- Zero
Correct Option: C
For path difference λ, phase difference = 2π rad. For path difference λ/4, phase difference
| = | rad. | 2 |
As K = 4I0 so intensity at given point where path difference is
| 4 |
| K' = 4I0 cos2 | ![]() | ![]() | ![]() | cos | = cos45° | ![]() | 4 | 4 |
| = 2I0 = | 2 |

