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In a diffraction pattern due to a single slit of width 'a', the first minimum is observed at an angle 30° when light of wavelength 5000 Å is incident on the slit. The first secondary maximum is observed at an angle of :
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sin-1 
1 
4 -
sin-1 2 3 -
sin-1 1 2 -
sin-1 3 4
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Correct Option: D
For the first minima,
| θ = | a |
| sin30° = | = | |||
| a | 2 |
First secondary maxima will be at
| sin θ = | = | | | |||||
| 2a | 2 | 2 |
| ⇒ θ = sin-1 = | | | 4 |
