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A coil of resistance 400Ω is placed in a magnetic field. If the magnetic flux φ (wb) linked with the coil varies with time t (sec) as φ = 50t2 + 4. The current in the coil at t = 2 sec is :
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- 0.5 A
- 0.1 A
- 2 A
- 1 A
Correct Option: A
According, to Faraday’s law of induction
Induced e.m.f.ε = - | = -(100t) | dt |
Induced current i at t = 2 sec.
= | = + | = + 0.5 A | ||||
R | 400 |