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Electromagnetic Induction

  1. A varying current in a coil changes from 10A to zero in 0.5 sec. If the average e.m.f induced in the coil is 220V, the self-inductance of the coil is
    1. 5 H
    2. 6 H
    3. 11 H
    4. 12 H
Correct Option: C

Initial current (I1) = 10 A; Final current(I2)= 0; Time (t) = 0.5 sec and induced e.m.f. (ε) = 220 V. ​Induced e.m.f. (ε)

= - L
dI
= - L
(I2 - I1)
dtt

= - L
(0 - 10)
= 20L
0.5

or, L =
220
= 11 H
20

[where L = Self inductance of coil]



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