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Electromagnetic Induction

  1. A 100 millinery coil carries a current of 1A. Energy stored in its magnetic field is​
    1. 0.5 J
    2. 1 A
    3. 0.05 J ​
    4. 0.1 J
Correct Option: C

E =
1
Li2
2

=
1
× (100 × 10-3) × 12 = 0.05 J
2



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