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If the linear density (mass per unit length) of a rod of length 3m is proportional to x, where x is the distance from one end of the rod, the distance of the centre of gravity of the rod from this end is
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- 2.5 m
- 1 m
- 1.5 m
- 2 m
Correct Option: D
Consider an element of length dx at a distance x from end A.
Here, mass per unit length λ of rod
λ ∝ x ⇒ λ = kx
∴ dm = λdx = kx dx
Position of centre of gravity of rod from end A.