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A wheel of radius 1m rolls forward half a revolution on a horizontal ground. The magnitude of the displacement of the point of the wheel initially in contact with the ground is
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- π
- 2π
- √2π
- √π² + 4
Correct Option: D
Linear distance moved by wheel in half revolution = πr. Point P1 after half revolution reaches at P2 vertically 2m above the ground.
∴ Displacement P1P1
= √π²r² + 2² = √π² + 4
[ ∵ r = 1m]