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A rod of weight W is supported by two parallel knife edges A and B and is in equilibrium in a horizontal position. The knives are at a distance d from each other. The centre of mass of the rod is at distance x from A. The normal reaction on A is
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Wd x -
W(d - x) x -
W(d - x) d -
Wx d
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Correct Option: C
By torque balancing about B
NA(d) = W (d – x)
| NA = | ||
| d |
