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A circular platform is mounted on a frictionless vertical axle. Its radius R = 2 m and its moment of inertia about the axle is 200 kgm². It is initially at rest. A 50 kg man stands on the edge of the platform and begins to walk along the edge at the speed of 1 ms-1 relative to the ground. Time taken by the man to complete one revolution is
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- πs
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3π s 2 - 2πs
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π s 2
Correct Option: C
Using conservation
Li = 0 (Initial moment)
Lƒ = mvR – Iω (Final moment)
According to the conservation of momentum
Li = Lƒ
⇒ mvR – I.ω = 0
mvR = I.ω
ω = (1/2)
(v + ωR)t = 2πR
t = | ![]() | 1 + | × 2 | ![]() | = 2 π × 2 | |
2 |
t = 2π sec.