-
The instantaneous angular position of a point on a rotating wheel is given by the equation θ(t) = 2t³ – 6t². The torque on the wheel becomes zero at
-
- t = 1s
- t = 0.5 s
- t = 0.25 s
- t = 2s
Correct Option: A
When angular acceleration (α) is zero then torque on the wheel becomes zero.
θ(t) = 2t³ – 6t²
| ⇒ | = 6t² - 12t ⇒ α = | = 12t - 12 = 0 | ||
| dt | dt |
∴ t = 1 sec.
