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A wheel having moment of inertia 2 kg-m² about its vertical axis, rotates at the rate of 60 rpm about this axis. The torque which can stop the wheel’s rotation in one minute would be
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π N - m 18 -
2π N - m 15 -
π N - m 12 -
π N - m 15
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Correct Option: D
τ × ∆t = L0
{∵ since Lƒ = 0}
⇒ τ × ∆t = Iω
or, τ × 60 = 2 × 2 × 60π/60
| τ = | N-m | |
| 15 |
