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Moment of inertia of a uniform circular disc about a diameter is I. Its moment of inertia about an axis ⊥ to its plane and passing through a point on its rim will be
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- 5 I
- 3 I
- 6 I
- 4 I
Correct Option: C
M.I of uniform circular disc about its diameter = I
According to theorem of perpendiclar axes,
M.I. of disc about its axis = | MR² = 2I | |
2 |
Applying theorem of | | axes, | ![]() | ∵ I = | mr² | ![]() | |
4 |
M.I of disc about the given axis
= 2I + mr² = 2I + 4I = 6I