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The two ends of a rod of length L and a uniform cross-sectional area A are kept at two temperatures T1 and T2 (T1 > T2). The rate of heat transfer, through the rod in a steady state is given by:
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dQ = K(T1 - T2) dt LA -
dQ = kLA (T1 - T2) dt -
dQ = KA(T1 - T2) dt L -
dQ = KL(T1 - T2) dt A
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Correct Option: C
| = | |||
| dt | L |
[(T1 - T2) is the temperature difference]
