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Consider a compound slab consisting of two different materials having equal thicknesses and thermal conductivities K and 2K, respectively. The equivalent thermal conductivity of the slab is
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4 K 3 -
2 K 3 - √3 K
- 3K
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Correct Option: A
In series, equivalent thermal conductivity
| Keq = | ||
| K1 + K2 |
| or, Keq = | = | K | ||
| K + 2K | 3 |
