-
Two rods of thermal conductivities K1 and K2, cross-sections A1 and A2 and specific heats S1 and S2 are of equal lengths. The temperatures of two ends of each rod are T1 and T2. The rate of flow of heat at the steady state will be equal if
-
-
K1 = K2 A1S1 A2S2 - K1A1 = K2A2
- K1S1 = K2S2
- A1S1 = A2S2
-
Correct Option: B
| Rate of heat flow for one rod = | (d → Length) | |
| d |
Rate of heat flow for other rod
| = | ||
| d |
| In steady state, | ||
| d |
| = | ⇒ K1A1 = K2A2 | |
| d |
