A transverse wave is represented by y = A sin (t–kx).

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A transverse wave is represented by y = A sin (t–kx). For what value of the wavelength is the wave velocity equal to the maximum particle velocity?

1. πA/2
2. πA
3. 2πA
4. A

Correct Option: C

y = A sin (ωt–kx)
Particle velocity,

v_p =	dy	A ω cos(ωt - kx)
	dt

v_{p max} = Aω
wave velocity = ω/k
∴ Aω = ω/k

i.e., A =	1	But k =	2π
	k		λ

∴ λ = 2πA