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The wave described by y = 0.25 sin (10πx – 2πt),where x and y are in meters and t in seconds, is a wave travelling along the:
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- –ve x direction with frequency 1 Hz.
- +ve x direction with frequency π Hz and wavelength λ = 0. 2 m.
- +ve x direction with frequency 1 Hz and wavelength λ = 0.2 m
- –ve x direction with amplitude 0.25 m and wavelength λ = 0.2 m
Correct Option: C
y = 0.25 sin (10 πx – 2πt)
Comparing this equation with the standard wave equation
y = asin (kx – ωt)
We get, k = 10π
⇒ 2p/1 ⇒ λ = 0.2 m
And ω = 2π or, 2πv = 2π ⇒ v = 1Hz.
The sign inside the bracket is negative, hence the wave travels in + ve x- direction.
