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The transverse wave represented by the equation
y + 4sin π sin(3x + 15t) has 6
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- amplitude = 4
- wavelength = 4(π/3)
- speed of propagation = 5
- period = π/15
Correct Option: C
Compare the given equation with standard form
y = r sin | ![]() | - | ![]() | ||
λ | T |
= 3,λ = | and | = 15 | ||||
λ | 3 | T |
T = | ||
15 |
Speed of propagation,
v = | = | = 5 | ||
T | 2π/15 |