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The number of possible natural oscillation of air column in a pipe closed at one end of length 85 cm whose frequencies lie below 1250 Hz are : (velocity of sound = 340 ms-1)
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- 4
- 5
- 7
- 6
Correct Option: D
In case of closed organ pipe frequency,
fn = (2n + 1)
for n = 0, f0 = 100 Hz
n = 1, f1 = 300 Hz
n = 2, f2 = 500 Hz
n = 3, f3 = 700 Hz
n = 4, f4 = 900 Hz
n = 5, f5 = 1100 Hz
n = 6, f6 = 1300 Hz
Hence possible natural oscillation whose frequencies < 1250 Hz = 6(n = 0, 1, 2, 3, 4, 5)