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A source and an observer move away from each other, with a velocity of 10m/s with respect to ground. If the observer finds the frequency of sound coming from the source as 1950 Hz, then original frequency of source is (velocity of sound in air = 340 m/s)
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- 1950 Hz
- 2068 Hz
- 2132 Hz
- 2486 Hz
Correct Option: B
According to Doppler's effect
n' = | ![]() | ![]() | n = | ![]() | ![]() | n = | × 1950 = 2068 Hz | |||||
v - vs | 340 + 10 | 350 |