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Each corner of a cube of side l has a negative charge, –q. The electrostatic potential energy of a charge q at the centre of the cube is
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4q² √2πε0l -
√2q² 4πε0l -
4q² √2πε0l -
- 4q² √3πε0l
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Correct Option: D
Length of body diagonal = √3l
∴ Distance of centre of cube from each corner
r = | l | |
2 |
P.E. at centre
= 8 × Potential Energy due to A
= 8 × | l | |
2 |
= 8 × | × 2 × q × (-q) = | ||
4πε0√3l | √3πε0l |