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Electrostatic Potential and Capacitance

  1. The capacity of a parallel plate condenser is 10 µF when the distance between its plates is 8 cm. If the distance between the plates is reduced to 4 cm then the capacity of this parallel plate condenser will be​​​
    1. 5 µF ​
    2. 10 µF
    3. 20 µF
    4. ​40 µF
Correct Option: C

C = 10 µF​
d = 8 cm ​
C' = ?
​d' = 4 cm

C =
A∊0
⇒ Cα
1
dd

​If d is halved then C will be doubled. ​
Hence, C' = 2C = 2 × 10 µF = 20 µF



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