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The capacity of a parallel plate condenser is 10 µF when the distance between its plates is 8 cm. If the distance between the plates is reduced to 4 cm then the capacity of this parallel plate condenser will be
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- 5 µF
- 10 µF
- 20 µF
- 40 µF
Correct Option: C
C = 10 µF
d = 8 cm
C' = ?
d' = 4 cm
C = | ⇒ Cα | |||
d | d |
If d is halved then C will be doubled.
Hence, C' = 2C = 2 × 10 µF = 20 µF