-
A proton and an alpha particle both enter a region of uniform magnetic field B, moving at right angles to field B. If the radius of circular orbits for both the particles is equal and the kinetic energy acquired by proton is 1 MeV the energy acquired by the alpha particle will be:
-
- 0.5 MeV
- 1.5 MeV
- 1 MeV
- 4 MeV
Correct Option: C
| As we know, F = qvB = | ||
| R |
| ∴ R = | = | ||
| qB | qB |
| Since R is same so, KE ∝ | ||
| m |
Therefore KE of α particle
| = | = | = 1MeV | ||
| m | 4 |
