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					 A charged particle of charge q and mass m enters perpendicularly in a magnetic field . Kinetic energy of the particle is E; then frequency of rotation is
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                        -  qB mπ 
-  qB 2πm 
-  2BE 2πm 
-  qB 2πE 
 
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Correct Option: B
For circular path in magnetic field, mrω² = qvB
| ⇒ ω² = | As v = rω | |
| mr | 
| ∴ ω² = | ⇒ ω = | |||
| mr | m | 
 ∴ If ν is frequency of roatation, then 
| v = | ⇒ v = | |||
| 2π | 2πm | 
 
	