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A charged particle of charge q and mass m enters perpendicularly in a magnetic field . Kinetic energy of the particle is E; then frequency of rotation is
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qB mπ -
qB 2πm -
2BE 2πm -
qB 2πE
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Correct Option: B
For circular path in magnetic field, mrω² = qvB
⇒ ω² = | As v = rω | |
mr |
∴ ω² = | ⇒ ω = | |||
mr | m |
∴ If ν is frequency of roatation, then
v = | ⇒ v = | |||
2π | 2πm |