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A long straight wire carries a certain current and produces a magnetic field of
2 × 10–4 = weber m²
at a perpendicular distance of 5 cm from the wire. An electron situated at 5 cm from the wire moves with a velocity 107 m/s towards the wire along perpendicular to it. The force experienced by the electron will be
(charge on electron =1.6 × 10–19 C)
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- Zero
- 3.2 N
- 3.2 × 10–16 N
- 1.6 × 10–16 N
Correct Option: C
Given: Magnetic field B = 2 × 10–4 weber/m²
Velocity of electron, v = 107 m/s
Lorentz force F = qvB sin θ
= 1.6 × 10–19 × 107 × 2 × 10–4 (∵ θ = 90°)
= 3.2 × 10–16 N