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A closed loop PQRS carrying a current is placed in a uniform magnetic field. If the magnetic forces on segments PS, SR, and RQ are F1 , F2 and F3 respectively and are in the plane of the paper and along the directions shown, the force on the segment QP is
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- F3 – F1– F2
- √(f3 - F1)² + F2²
- √(f3 + F1)² + F2²
- F3 – F1 + F2
Correct Option: B
According to the figure the magnitude of force on the segment QM is F3 – F1 and PM is F2. 
Therefore, the magnitude of the force on segment PQ is √(F3 - F1)² + F2²
