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A circuit contains an ammeter, a battery of 30V and a resistance 40.8Ω all connected in series. If the ammeter has a coil of resistance 480Ω and a shunt of 20Ω, the reading in the ammeter will be:
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- 0.25 A
- 2A
- 1 A
- 0.5 A
Correct Option: D
From circuit diagram 
| Resistance of ammeter = | = 19.2Ω. | |
| 480 + 20 |
Total resistance R = 40.8 + 19.2 = 60Ω
Reading in the ammeter i = V/R
| = | = 0.5 A | |
| 40.8 + 19.2 |
